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To solve this query, we will be using sorted() and findFirst() methods of Stream.ĮmployeeList.stream().sorted(paringInt(Employee::getYearOfJoining)).findFirst() Įmployee seniorMostEmployee = seniorMostEmployeeWrapper.get() Query 3.9 : Who has the most working experience in the organization?įor this query, sort employeeList by yearOfJoining in natural order and first employee will have most working experience in the organization. ("Salary : "+youngestMaleEmployeeInProductDevelopment.getSalary()) ĭetails Of Youngest Male Employee In Product Development : ("Year Of Joinging : "+youngestMaleEmployeeInProductDevelopment.getYearOfJoining())

("Age : "+youngestMaleEmployeeInProductDevelopment.getAge()) ("Name : "+youngestMaleEmployeeInProductDevelopment.getName()) ("ID : "+youngestMaleEmployeeInProductDevelopment.getId()) ("Details Of Youngest Male Employee In Product Development") min(paringInt(Employee::getAge)) Įmployee youngestMaleEmployeeInProductDevelopment = youngestMaleEmployeeInProductDevelopmentWrapper.get()

filter(e -> e.getGender()="Male" & e.getDepartment()="Product Development")

Optional youngestMaleEmployeeInProductDevelopmentWrapper=